||||
相对论、量子力学及其场论的,本质、规律,及其必然且必需的发展(47)
可变系加速度1-线矢
(接(46))
可变系加速度1-线矢;
[矢a(X)]=d[矢v(X)]/dt(X)
=d[(dr(X,x)/dt(X))W(X,x)[基矢X(x)],x=0到3求和]/dt(X)
=[(((d^2r(X,x)/dt(X)^2)W(X,x)+(dr(X,x)/dt(X))dW(X,x)/dt(X))[基矢X(x)]
+(dr(X,x)/dt(X))W(X,x)d[基矢X(x)]/dt(X)),x=0到3求和]
=[(((d^2r(X,x)/dt(X)^2)W(X,x)+(dr(X,x)/dt(X))dW(X,x)/dt(X))[基矢X(x)]
-(dr(X,x)/dt(X))W(X,x)[(dl(A,a’)/dt(X))w(Ax’,xa’)[基矢X(x’)]
,a’,x’=0到3求和],x=0到3求和]
=[(((d^2r(X,x)/dt(X)^2)W(X,x)
+(dr(X,x)/dt(X))(dW(X,x)/dt(X))+W(X,x’)(dl(A,a’)/dt(X))w(Ax,x’a’)))[基矢X(x)]
,a’,x’,x=0到3求和],
只是当全部w(Ax,x‘a’)=0,x,x‘,a=0,1,2,3, W(X,x)=1,才简化为惯性牵引、不变系的加速度1-线矢:
[矢a(A)]=d[矢v(A)]/dt(A)=[(((d^2r(A,a)/dt(A)^2)[基矢A(a)],a=0到3求和],
(未完待续)
Archiver|手机版|科学网 ( 京ICP备07017567号-12 )
GMT+8, 2024-5-22 10:28
Powered by ScienceNet.cn
Copyright © 2007- 中国科学报社